Skip to main content

How to design a Node in Tree?

How to design a Node in Tree?

There are three main components of a tree in a node.

 1) Integer holding data.
2) Left pointer holding node in a left subtree.
3) Right pointer holding node in a right subtree.

The following design is having data of int type and left,right pointers of a node to the subtrees.

package com.BST;

public class Node {

 int data;
 Node left;
 Node right;
  * @return the data
 public Node(int data)
 public int getData() {
  return data;
  * @param data the data to set
 public void setData(int data) { = data;
  * @return the left
 public Node getLeft() {
  return left;
  * @param left the left to set
 public void setLeft(Node left) {
  this.left = left;
  * @return the right
 public Node getRight() {
  return right;
  * @param right the right to set
 public void setRight(Node right) {
  this.right = right;
 /* (non-Javadoc)
  * @see java.lang.Object#toString()
 public String toString() {
  return "Node [data=" + data + ", left=" + left + ", right=" + right
    + "]";




Popular posts from this blog

Heap implementation in JAVA

In this tutorial we will see all the functionalities of heaps implemented through java language.

package com.problems.heap;publicclassHeapFunctions{//Function to generate maxheapify where root is max than childspublicvoidmaxHeapify(int Arr[],int i,int N){int largest;int left =2*i+1;//left childint right =2*i +2;//right child System.out.println("left"+" "+left); System.out.println("right"+" "+right); System.out.println("Max size"+" "+N);if(left< N && Arr[left]> Arr[i]){ largest = left; System.out.println("largest left"+largest);}else{ largest = i; System.out.println("largest i"+largest);}if(right < N && Arr[right]> Arr[largest]){ largest = right; System.out.println("largest right"+largest);}if(largest != i ){ System.out.println("No largest"+largest); Arr=swap (A…

Solved: The index 1 is out of range.

This error usually comes when we try to insert data in a query where there is no index defined for it.
Example :-
String strQuery=“select * from location where city_id=? ”;
The question mark will be the the first index if we want to insert data so if we call a function like-
oPreparedStatement = oConnection.prepareStatement(strQuery);
here we are sending 235 as a first parameter so it will work fine but as soon as we write something after it like
then it will throw “The index 2 is out of range” since there is no place to send this value in a query hence it will throw the same error. Here index defines the parameter for which there is no place in the query.
To rectify this we need to write query like-
String strQuery=“select * from location where city_id=? And city_name=? ”;
then it will work fine.
The cases in which these errors can occur is-
1)Query is coming out as null. 2)No of parameters are more than the parameters p…