https://leetcode.com/problems/two-sum/
Given an array of integers nums
and an integer target
, return indices of the two numbers such that they add up to target
.
You may assume that each input would have exactly one solution, and you may not use the same element twice.
You can return the answer in any order.
Example 1:
Input: nums = [2,7,11,15], target = 9 Output: [0,1] Output: Because nums[0] + nums[1] == 9, we return [0, 1].
Example 2:
Input: nums = [3,2,4], target = 6 Output: [1,2]
Example 3:
Input: nums = [3,3], target = 6 Output: [0,1]
class Solution {
public int[] twoSum(int[] nums, int target) {
HashMap<Integer,Integer> map=new HashMap<Integer,Integer>();
for(int i=0;i<nums.length;i++){
if(map.get(nums[i])==null){
map.put(target-nums[i],i);
}
else{
return new int[]{map.get(nums[i]),i};
}
}
return null;
}
}
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